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1 + sinx cosx = cos2x + (1 + sinx)2 (1 + sinx) (cosx) = cos2x + 1 + 2sinx + sin2x (1 + sinx) (cosx) = 2 + 2sinx (1 + sinx) (cosx) = 2 (1 + sinx) (1 + sinx) (cosx) = 2 cosx = 2secx Upvote • 1 Downvote

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Secant, cosecant and cotangent, almost always written as sec, cosec and cot are trigonometric functions like sin, cos and tan. sec x = 1. cos x. cosec x = 1. sin x. cot x = 1 = cos x. tan x sin x. Not

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1 Hint The appearance of 1 + cos x suggests we can produce an expression without a constant term in the denominator by substituting x = 2 t and using the half-angle identity cos 2 t = 1 2 ( 1 + cos 2

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1 + sin x 1-sin x × 1 + sin x 1 + sin x 1 + sin x 2 1 2-sin 2 x 1 + sin x 2 cos 2 x 1 + sin x cos x 2 1 cos x + sin x cos x 2 s e c x + tan x 2. Hence, 1 + sin x 1-sin x = s e c x + tan x 2. Suggest C

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#1 1+sinx/cosx + cosx/1+six = 2secx 1+sin (1+sin)/cos (1+sin) + (cos)cos/cos (1+sin) = 2sec (1+sin)^2/cos (1+sin) + cos^2/cos (1+sin) =2sec I am not sure what to do next. Need help. Thanks Tim skeeter

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Found 2 solutions by josgarithmetic, Boreal: Answer by josgarithmetic (37903) ( Show Source ): You can put this solution on YOUR website! Answer by Boreal (15189) ( Show Source ): You can put this sol

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Prove : 1 + cosx + sinx/1 + cosx - sinx = 1 + sinx/cosx Question Prove : 1+cosx−sinx1+cosx+sinx= cosx1+sinx Easy Solution Verified by Toppr LHS 1+cosx−sinx1+cosx+sinx Dividing and multiplying by cosx

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Sep 7, 2021Proof trigonometric identities. 1−sin⁡(−x)cos⁡x+cos⁡(−x)sin⁡x=sec⁡x. Jerold . Answered. 2021-09-07

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The equation sin 2 x + cos 2 y = 2 sec 2 z is only solvable when ∣ sin x ∣ = 1, ∣ cos y ∣ = 1 and ∣ sin z ∣ = 1, where x, y, z ∈ R because Reason Maximum value of ∣ sin x ∣ and ∣ cos y ∣ is 1 and mini

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Jul 18, 2021(1-sinx+cosx)^2 = 2(1+sinx)(1+cosx) - 24254311. If you're trying to establish an identity, the given equation is not an identity.The proper identity would be as follows:

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Does cosx + sinx = 1? A JohnLight 2 If cos^2 x + sin^2 x = 1, does cos x + sin x = 1? I'm not sure because, cos^2 x = (cosx)^2 therefore when you take the square root you get cos x. So if you take the

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Write each expression with a common denominator of (1+cos(x))(1− cos(x)) ( 1 + cos ( x)) ( 1 - cos ( x)), by multiplying each by an appropriate factor of 1 1. Tap for more steps... Combine the numerat

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prove that a) sinx-cosx+1/sinx+cosx-1=secx+tanx b)if 2cosx+sinx=1,the - askIITians × Learn Science & Maths Concepts for JEE, NEET, CBSE @ Rs. 99! Register Now Junior Hacker One to One Call us on 1800-

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Solution for 8-Solve the equations (2sinx-1)cosx=0. Q: Find the solution of the exponential equation 2t 1000 (1.08)²t 50,000 in terms of logarithms, or… A: The given expression is 10001.082t=50,000 We

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The limit of the function in exponent position expresses a limit rule. According to the trigonometric limit rules, the limit of sinx/x as x approaches 0 is equal to one. = ( lim x → 0 ( 1 + sin x) 1 s

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